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First, we'll factorize by x the denominator:
1/(x^2+x) = 1/x(x+1)
We notice that the denominator of the right side ratio is the least common denominator of 2 irreducible ratios.
We'll suppose that the ratio 1/x(x+1) is the result of addition or subtraction of 2 elementary fractions:
1/x(x+1) = A/x + B/(x+1) (1)
We'll multiply the ratio A/x by (x+1) and we'll multiply the ratio B/(x+1) by x.
1/x(x+1)= [A(x+1) + Bx]/x(x+1)
Since the denominators of both sides are matching, we'll write the numerators, only.
1 = A(x+1) + Bx
We'll remove the brackets:
1 = Ax + A + Bx
We'll factorize by x to the right side:
1 = x(A+B) + A
If the expressions from both sides are equivalent, the correspondent coefficients are equal.
A+B = 0
A = 1
1 + B = 0
B = -1
We'll substitute A and B into the expression (1):
1/x(x+1) = 1/x - 1/(x+1)
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