Assuming the side of the square is s.

For the first square, the area of the circle is:

`(pis^2)/4`

For the second square, the radius of each circle is s/4 and the area of the four circles is:

`4(pis^2)/16=(pis^2)/4`

For the third square, the radius of each circle is s/6...

## Read

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

Assuming the side of the square is s.

For the first square, the area of the circle is:

`(pis^2)/4`

For the second square, the radius of each circle is s/4 and the area of the four circles is:

`4(pis^2)/16=(pis^2)/4`

For the third square, the radius of each circle is s/6 and the area of the nine circles is:

`9(pis^2)/36=(pis^2)/4`

**Therefore the area is the same for each square.**

For the fourth square, the radius of each circle is s/8 and the area of the 16 circles is:

`16(pis^2)/64=(pis^2)/4`