Assuming the side of the square is s.
For the first square, the area of the circle is:
`(pis^2)/4`
For the second square, the radius of each circle is s/4 and the area of the four circles is:
`4(pis^2)/16=(pis^2)/4`
For the third square, the radius of each circle is s/6...
Read This Answer Now
Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.
Already a member? Log in here.
Assuming the side of the square is s.
For the first square, the area of the circle is:
`(pis^2)/4`
For the second square, the radius of each circle is s/4 and the area of the four circles is:
`4(pis^2)/16=(pis^2)/4`
For the third square, the radius of each circle is s/6 and the area of the nine circles is:
`9(pis^2)/36=(pis^2)/4`
Therefore the area is the same for each square.
For the fourth square, the radius of each circle is s/8 and the area of the 16 circles is:
`16(pis^2)/64=(pis^2)/4`