Since the initial velocity is 34.3 m/s with initial height of 2.1 m, then upon substituting into the height formula, we get:
The corresponding velocity formula for constant acceleration is
And the maximum height is found when v=0. This gets:
`0=-9.8 t+34.3` solve for t
`9.8t=34.3` divide by 9.81
The object reaches maximum height at 3.5 seconds after launch. This is now substituted into the height formula to get:
The maximum height is 62.1m and the time it occurs is at 3.5 s.