For the formation of NH_3 from N_2 and H_2 ,
N_2(g)+3H_2(g)----->2NH_3(g), K_p = 4.34 *10^-3 at 300^0 C.
So what is the value of K_p for the reverse reaction ?
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We have given chemical equation
We have given
Kp=4.34 x10 ^(-3)
Thus Kp for original equation is 4.34 x 10^(-3) .
We need to calculate Kpr for the following equation
2NH_3 -> N_2 +3H_2
which is the reverse of the original reaction, Thus
=1/(4.34 x 10^(-3))
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