In the following reaction predict the moles of ammonia that can be made using 22.4 g of nitrogen and an unlimited amount of hydrogen. N2(g) + 3H2(g) -> 2NH3(g)
The chemical reaction given is that of nitrogen and hydrogen reacting to give ammonia.
N2(g) + 3H2(g) --> 2NH3(g)
From the equation of the chemical reaction it is seen that 1 mole of nitrogen gas (N2) or 2 moles of nitrogen (N) combine with 3 moles of hydrogen gas (H2) to give 2 moles of ammonia.
The molar mass of nitrogen (N) is 14 g/mole. 22.4 g of nitrogen N is equivalent to 22.4/14 moles of nitrogen. When this reacts with an unlimited amount of hydrogen the number of moles of ammonia formed in the product is equal to the number of moles of nitrogen in the reactants.
The number of moles of ammonia that is formed under the given conditions is 1.6 mole.
As the molar mass of ammonia is 17, the mass of ammonia formed is 17*1.6 = 27.2 g.
`N_2+3H_2 rarr 2NH_3`
Molar mass of `N_2` = 28g/mol
Amount of `N_2` moles `= 22.4/28mol = 0.8mol`
`N_2:NH_3 = 1:2`
Since we have unlimited `H_2` the full reaction will takes place and `NH_3` will form until all the `N_2` is finished.
Amount of `NH_3` formed `= 2xx0.8 = 1.6mol`
So we can made 1.6moles of ammonia.