The following data were collected for the reaction M + N --> P +Q The following data were collected for the reaction M + N --> P + Q Init.cntrtn init. rate (mol L^-1s^-1) M ...
The following data were collected for the reaction M + N --> P +Q
The following data were collected for the reaction M + N --> P + Q
Init.cntrtn init. rate (mol L^-1s^-1)
M N
.010 .010 R1 2.5x10^-6
.020 .010 R2 5.0x10^-6
.020 .030 R3 4.5x10^-5
what is the rate law ?what is value of the rate constant with correct units
- print Print
- list Cite
Expert Answers
calendarEducator since 2012
write937 answers
starTop subjects are Science, Math, and Social Sciences
The rate law is an equation that can determine how fast the reaction will proceed. For this problem, we can write the rate law as:
rate = k [M]^x [N]^y
x and y are variables that can be derived from the given rate and concentrations.
1. Isolate the [M]. To do that, we try to inspect which among the table has constant value of [N]. We can see that Rates 1 and 2 has same value for [N]. Now we can solve for x
rate 1 (0.01)^x 2.5x10^-6
------ = --------- = -------------
rate 2 (0.02)^x 5.0x10^-6
= (1/2)^x = 1/2
**solve for x
X = 1
2. Now do the same thing for [N]. We can see rate 2 and 3 has the same number of [M] and therefore we can isolate [N].
rate 2 (0.01)^y 5.0x10^-6
------ = --------- = -------------
rate 3 (0.03)^y 4.5x10^-5
5. The order of the equation is the sum of the exponent x and y. Therefore the order of the equation is 3rd order.
Related Questions
Unlock This Answer Now
Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.