Note :- 1) If y = x^n ; where n = constant, then dy/dx = n*(x^(n-1))

2) If y = n*x ; where n = constant ; then dy/dx = n

Now,

`y = 1/(5x+1)^2`

`or, y = (5x+1)^-2`

`thus, dy/dx = y' = -2*{(5x+1)^-3}*5`

`or, y' = -10/{(5x+1)^3}`

``

Note :- 1) If y = x^n ; where n = constant, then dy/dx = n*(x^(n-1))

2) If y = n*x ; where n = constant ; then dy/dx = n

Now,

`y = 1/(5x+1)^2`

`or, y = (5x+1)^-2`

`thus, dy/dx = y' = -2*{(5x+1)^-3}*5`

`or, y' = -10/{(5x+1)^3}`

``