finding an angle what is the x angle if 2sin2x+square root 2=0?
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justaguide
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We have to solve 2*sin 2x + sqrt 2 = 0
2*sin 2x + sqrt 2 = 0
=> 2*sin 2x = -sqrt 2
=> sin 2x = -1/sqrt 2
2x = arc sin (-1/sqrt 2)
=> 2x = -45 and -135
x = -45/2 + n*180 and x = -135/2 + n*180
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giorgiana1976 | Student
We'll move the numer alone to the right side:
2sin 2x = -sqrt2
We'll divide by 2:
sin 2x = -sqrt2/2
2x = (-1)^k*arcsin (-sqrt2/2) + kpi
2x = -pi/4 + kpi
We'll divide by 2:
x = -pi/8 + kpi/2
All the angles x = -pi/8 + kpi/2, where k is an integer number, verify the equation 2sin2x+square root 2=0.
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