# Find y' for y=y(x) defined implicitly by 5y^2-8x^4+3=0 and evaluate y' at (x,y)=(1,1)

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The derivative `dy/dx` has to be determined of 5y^2 - 8x^4 + 3 = 0 where y is s function of x. The value of `dy/dx` has to be determined at (1, 1).

Use implicit differentiation on 5y^2 - 8x^4 + 3 = 0

=> `10y*((dy)/(dx)) - 32x^3 = 0`

=> `dy/dx = (32*x^3)/(10*y)`

=> `dy/dx = (3.2*x^3)/y`

The value of `dy/dx` at the point (1,1) is 3.2

**The derivative `dy/dx` = `(3.2*x^3)/y` and its value at (1,1) is 3.2**