find y' for y=e^(sin(42x)) use the 3 fold chain rule if you can

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You should remember that you need to use the chain rule when you should evaluate the derivative of composition of functions such that:

`(f(g(x)))' = f'(g(x))*g'(x)*x'`

Reasoning by analogy yields:

`(dy)/(dx) = (d(e^(sin(42x))))/(dx)`

`(dy)/(dx) = (d(e^(sin(42x))))/(dx)*(d(sin (42 x)))/(dx)*(d(42x))/(dx)`

`(dy)/(dx) = e^(sin(42x))*cos(42x)*42`

Hence, evaluating the derivative of the given composition of functions, using the chain rule, yields `(dy)/(dx) = 42e^(sin(42x))*cos(42x).`

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