We have to find x and y given x(1+2i)+y(2-i)=4+3i

x(1+2i)+y(2-i)=4+3i

=> x + 2xi + 2y - yi = 4 + 3i

equate the real and imaginary coefficients

x + 2y = 4 and 2x - y = 3

x = 4 - 2y

substitute in 2x - y = 3

=> 8 - 4y - y = 3

=> y = 1

x = 2

**The value of x = 2 and y = 1**

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