We have to find x and y given x(1+2i)+y(2-i)=4+3i
x(1+2i)+y(2-i)=4+3i
=> x + 2xi + 2y - yi = 4 + 3i
equate the real and imaginary coefficients
x + 2y = 4 and 2x - y = 3
x = 4 - 2y
substitute in 2x - y = 3
=> 8 - 4y - y = 3
=> y = 1
x = 2
The value of x = 2 and y = 1
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