Find the x intercepts of the graph of y = -x^2 + 3x + 18
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calendarEducator since 2008
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y= -x^2 + 3x + 18
We need to find the x-intercept of the curve y.
The x-intercept is the point where the curve y meets the x-axis.
Then the values of y would be zero.
==> -x^2 + 3x + 18 = 0
==> We will factor -1.
==> -(x^2 -3x -18) = 0
Now we will factor.
==> -(x-6)(x+3) = 0
==> x = 6 , -3
There are 2 values for x. Then, the curve y meets the x-axis at two points ( 6,0) and (-3,0)
Then x-intercepts are (6,0) and (-3,0)
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calendarEducator since 2010
write12,544 answers
starTop subjects are Math, Science, and Business
We have the graph : y = -x^2 + 3x + 18
At the x-intercept y = 0
So to find the x- intercept we equate
-x^2 + 3x + 18 = 0
=> x^2 - 3x - 18 = 0
=> x^2 - 6x + 3x - 18 = 0
=> x(x - 6) + 3( x - 6) = 0
=> (x + 3)(x - 6) = 0
Therefore the x intercepts are:
( -3 , 0) and ( 6, 0)
find x intercepts of y = -x^2 + 3x + 18.
The x intercepts of a graph are the points on x axis where the graph intersects. On x axis y coordinate is zero always.
To find the x intercept of y = -x^2+3x+18, we put y = 0 and solve for x.
0 = -x^2+3x+18.
We subtract -x^2+3x+18 from both sides:
=> x^2-3x-18 = 0.
=> (x+6)(x-3) = 0.
So x+6 = 0 or x-3 = 0.
So the x intercepts of the graph are x = -6 or x = 3.
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