# find the x-intercept and the y-intercept for the graph of the question x+2y=10

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x+2y =10

To find where the function intersect with x-axis, then x will be 0:

0+2y =10

==> y= 5

Then the function intersect with the x-axis at the point (0,5)

Now the function intersect with the y-axis when y=0 ,

==> x+ 2(0) =10

==> x= 10

Then the function intersect with the y-axis at the point (10,0).

To find the intercepts of a graph with an axis , we have to calculate f(x)=0 and f(0).

When calculating f(x)=0, we'll find the interception of the graph with x axis.

We'll re-write the given equation:

x+2y=10

We'll isolate the term in y, to the left side:

2y = 10-x

We'll divide by 2:

y = 5 - x

Now, we'll calculate f(x)=0, that means that y=0.

0 = 5 - x

We'll move x to the left side:

**x = 5**

The interception point of the graph with x axis is: (5,0).

Now, we'll calculate the interception point with y axis and for this reason, we'll put x=0.

y = 5 - 0

**y = 5**

The interception point of the graph with y axis is: (0,-3).

x + 2y = 10

For the x-intercept; the y value = 0, so:

x = 2(0) = 10

x = 10

For the y-intercept; the x value = 0 so:

0 + 2y = 10

2y = 10

y = 10/2 = 5

x+2y=10

x+2y-x=10-x

2y=10-x

2y/2=10/2-x/2

y=5-x

y=5-0

y=5

x+2y=10

x+2y-2y=10-2y

x=10-2y

x=10-2(0)

x=10

To find the x and y intercepts ofx +y= 10

Solution:

We know that x/a +y/b =1 is called the standard intercept form of the line where a and b are the x and y intercepts of the line .

Given line is : x+2y = 10. Dividing by 10 we get:

x+2y/10 = 1. Or

x/1 + y/5 = 1 which is in intercpt form.So equating the coefficients,

x intercept = a = 1 and

y intercept = b = 5.

Teacher Hala, you have mistaken, because you are confusing the axis.

The answer (E.g. "the function intersect with x-axis, then x will be 0") is wrong.