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To find where the function intersect with x-axis, then x will be 0:
==> y= 5
Then the function intersect with the x-axis at the point (0,5)
Now the function intersect with the y-axis when y=0 ,
==> x+ 2(0) =10
==> x= 10
Then the function intersect with the y-axis at the point (10,0).
To find the intercepts of a graph with an axis , we have to calculate f(x)=0 and f(0).
When calculating f(x)=0, we'll find the interception of the graph with x axis.
We'll re-write the given equation:
We'll isolate the term in y, to the left side:
2y = 10-x
We'll divide by 2:
y = 5 - x
Now, we'll calculate f(x)=0, that means that y=0.
0 = 5 - x
We'll move x to the left side:
x = 5
The interception point of the graph with x axis is: (5,0).
Now, we'll calculate the interception point with y axis and for this reason, we'll put x=0.
y = 5 - 0
y = 5
The interception point of the graph with y axis is: (0,-3).
x + 2y = 10
For the x-intercept; the y value = 0, so:
x = 2(0) = 10
x = 10
For the y-intercept; the x value = 0 so:
0 + 2y = 10
2y = 10
y = 10/2 = 5
To find the x and y intercepts ofx +y= 10
We know that x/a +y/b =1 is called the standard intercept form of the line where a and b are the x and y intercepts of the line .
Given line is : x+2y = 10. Dividing by 10 we get:
x+2y/10 = 1. Or
x/1 + y/5 = 1 which is in intercpt form.So equating the coefficients,
x intercept = a = 1 and
y intercept = b = 5.
Teacher Hala, you have mistaken, because you are confusing the axis.
The answer (E.g. "the function intersect with x-axis, then x will be 0") is wrong.
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