# find x in the equation below. logx-log32+2log8 = 0 All are in base 'a'.

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### 1 Answer

We know the following rules in logarithm.

`loga+logb = log(ab)`

`loga-logb = log(a/b)`

`loga^b = bloga`

`log_a(x)-log_a32+2log_a8 = 0`

`log_a((x*8^2)/32) = 0`

`log_a(2x) = log_a1`

`2x = 1`

`x = 1/2`

*So the answer is x = 1/2*

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