The equation 2x^3 + 9x^2 -18x = 0 has to be solved.
2x^3 + 9x^2 -18x = 0
=> x*(2x^2 + 9x - 18) = 0
=> x*(2x^2 + 12x - 3x - 18) = 0
=> x*(2x(x + 6) - 3(x + 6)) = 0
=> x*(2x-3)(x + 6) = 0
This gives x = 0
2x - 3 = 0
=> x = 3/2
x + 6 = 0
=> x = -6
The solutions of the equation are {-6, 0, 3/2}
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