a) Find the vertical asymptotes of the function `y = (x^2 + 1)/(3x - 2x^2)`  b) Confirm your answer to part (a) by graphing the function.

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baxthum8 | High School Teacher | (Level 3) Associate Educator

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The vertical asymptotes are the values which x can not equal.  Therefore, `` `` 0

In order to find the zeroes solve: `3x-2x^2=0`

Factor to get: `x(3-2x)=0`

Use the zero property to solve for x. Set each factor equal to zero.

x = 0 and 3-2x=0

Therefore x=0, and x=`3/2`

Since x cannot equal these 2 values because it will make your denominator equal to 0 which would be undefined, the vertical asymptotes are: `x=0 and x=w3/2`

 

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zaurenwhilst | Student, Undergraduate | eNotes Newbie

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equate the denominator to 0 and solve for x

you will have two answers

X=0, and x=3/2 which are vertical assypmtotes

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