Find values of z for which f(z) = 5 given f(z) = l 2z + 3 l l 2z + 3 l : those lines are the symbols used in absolute values.
To solve for z, plug-in the value of f(z).
Then, apply the property of absolute value which is if |x|=a, then `x=+-a` .
So removing the absolute value sign results to:
`+-5 = 2z + 3`
Then, isolate z. To do so, subtract both sides by 3.
And divide both sides by 2.
`z=(5-3)/2=2/2 = 1`
Hence, the values of z are -4 and 1.