Find the values of sinx, tanx, secx, and cscx if cosx = 0.23

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We have cos x = .23

sin x = sqrt (1 - (cos x)^2) = sqrt ( 1 - .23^2) = .9731

tan x = sin x / cos x = .973 / .23 = 4.2312

sec x = 1/ cos x = 1/ .23 = 4.3478

cosec x = 1/ sin x = 1/ .973 = 1.0277

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Given cos(x) = 0.23

We need to find sin(x), tan(x) , sec(x), and (csc(x).

First, we know that sec(x) = 1/cos(x).

==> sec(x) = 1/(0.23) = 4.3478.

==> sec(x) = 4.3478.

Now we will use the trigonometric identities to find sin(x).

We know that:

sin^2 x + cos^2 x = 1

==> sin(x) = sqrt(1-cos^2x)

                = sqrt(1-0.23^2)

                = sqrt(0.9471)

                 = 0.9732

==> sin(x) = 0.9732.

Now we know that csc(x) = 1/sin(x)

==> csc(x) = 1/(0.9732) = 1.0275

==> csc(x) = 1.0275

Now we know that tan(x) = sin(x)/ cos(x).

==> tan(x) = 0.9732/ 0.23 = 4.2313

==> tan(x) = 4.2313

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