Find the values of "a" for the line y= ax - 8 if it intercepts the x axis at the point where x=2.

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We have the x-intercept of the line y = ax - 8 as x = 2.

Now we can rewrite y = ax - 8

y = ax - 8

=> ax - y =8

=> ax/8 - y/8 = 1

This is of the form x/a + y/b= 1, where a and b are the intercepts.

Therefore 8/a = 2

=> a = 4

Therefore we get the value of a as 4.

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Given the line y = ax-8

Also, given that the line (y) intercepts with the x-axis at the point x=2.

Then the values of y when x =2  is 0.

Then, we know that the point (2,0) is on the line y.

Let us substitute.

==> y= ax-8

==> 0 = 2a -8

==> 2a = 8

==> a = 4

==> y= 4x -8

Then, the values of a is 4.

 

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