We have the x-intercept of the line y = ax - 8 as x = 2.

Now we can rewrite y = ax - 8

y = ax - 8

=> ax - y =8

=> ax/8 - y/8 = 1

This is of the form x/a + y/b= 1, where a and b are the intercepts.

Therefore 8/a = 2

=> a = 4

**Therefore we get the value of a as 4.**

Given the line y = ax-8

Also, given that the line (y) intercepts with the x-axis at the point x=2.

Then the values of y when x =2 is 0.

Then, we know that the point (2,0) is on the line y.

Let us substitute.

==> y= ax-8

==> 0 = 2a -8

==> 2a = 8

**==> a = 4**

**==> y= 4x -8**

**Then, the values of a is 4.**

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