We have to solve 2a-5 < 5(a-1) for a.
2a-5 < 5(a-1)
open the brackets
=> 2a - 5 < 5a - 5
=> 2a - 5a < -5 + 5
=> -3a < 0
=> -a < 0
=> a > 0
Therefore a > 0
Given the inequality:
2a -5 < 5 (a-1)
We need to find all values of a that satisfies the inequality.
First we will open the brackets.
==> 2a -5 <5a -5
==> Now we will combine like terms.
==> 2a -5a < -5 + 5
==> -3a < 0
==> a > 0
Then the values of a that satisfies the inequality are when a is positive.
==> a belongs to the interval (0, inf )
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