We have to solve 2a-5 < 5(a-1) for a.

2a-5 < 5(a-1)

open the brackets

=> 2a - 5 < 5a - 5

=> 2a - 5a < -5 + 5

=> -3a < 0

=> -a < 0

=> a > 0

**Therefore a > 0**

Given the inequality:

2a -5 < 5 (a-1)

We need to find all values of a that satisfies the inequality.

First we will open the brackets.

==> 2a -5 <5a -5

==> Now we will combine like terms.

==> 2a -5a < -5 + 5

==> -3a < 0

==> a > 0

Then the values of a that satisfies the inequality are when a is positive.

**==> a belongs to the interval (0, inf )**

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