# Find the value of the discriminant of 6p^2 - 2p - 3 = 0

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6p^2 - 3p - 3 = 0

The discriminant is the value of delta:

delta = (b^2 - 4ac)

= 9 - 4*6*-3

= 9 + 72 = 81

==> delta = 81

Since delta is a positive perfect square then the function has two rational roots.

`6p^2 - 2p - 3 = 0 ` the formula for the discriminant is `b^2-4ac`

`a=6 ` `b=-2` `c=-3` plug in these numbers into the formula

`-2^2-4(6)(-3) ` simplify it

`4+72=76` the discriminant is 76. Since the discriminant is more than 0 the problem has 2 real solutions

The value is computed using the formula:

delta = b^2 - 4ac

We'll identify a,b,c which are the coefficients of the given equation:

6p^2 - 2p - 3 = 0

a = 6

b = -2

c = -3

We'll substitute the coefficients in the formula of delta:

delta = (-2)^2 - 4*(6)(-3)

delta = 4 + 72

**The discriminant of the quadratic is: delta = 76**