Find the value of c such that the line y=1/6x+3/2 is tangent to the curve y=(c)sqrt(x)
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nathanshields
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Tangent means the functions pass through the same point and have the same slope at that point.
So the derivatives must be equal:
`1/6=c/(2sqrt(x))`
And the y-values must also be equal (since the graphs pass...
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