You need to evaluate the unit vector that has the same direction with the vector `<-5,-5>` , hence, you need to remember the definition of the unit vector such that:

`bar u_1 = <-5/|bar u|,-5/|bar u|>`

You need to evaluate the length of the vector ` bar u` , such that:

`|bar u| = sqrt((-5)^2+(-5)^2)`

`|bar u| = sqrt(50) = 5sqrt2`

`bar u_1 = <-5/(5sqrt2),-5/(5sqrt2)>`

`bar u_1 = <-sqrt2/2,-sqrt2/2>`

**Hence, evaluating the unit vector that has the same direction with `bar u` yields `bar u_1 = <-sqrt2/2,-sqrt2/2>` .**

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