The sum of two consecutive numbers s given as 129. Let the numbers be n and n + 1

We have n + n + 1 = 129

=> 2n + 1 = 129

=> 2n = 129 - 1

=> 2n = 128

=> n = 128/2

=> n = 64

** The required numbers are 64...**

(The entire section contains 2 answers and 103 words.)

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