# Find three consecutive integers whose sum is equal to 366

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The sum of three consecutive numbers is 366. Let the numbers be n , n + 1 and n + 2

Now n + n + 1 + n + 2 = 366

=> 3n + 3 = 366

=> 3n = 363

=> n = 363/3

=> n = 121

**The required numbers are 121, 122 and 123.**

Let us assume that the first integer is n. Then the next integer is (n+1) and the third integer is (n+2)

Given that the sum of the three integers is 366

Then we will write as algabraic expression.

==> n + (n+1) + (n+2) = 366

Now we will combine like terms.

==> 3n + 3 = 366

Now we will subtract 3 from both sides.

==> 3n = 363

Now we will divide by 3.

==> n = 121

==> n+1 = 122

==> n+2 = 123

**Then, the three consecutive integers are 121, 122, and 123.**