Before taking the sum, determine the common ratio between consecutive terms.

`r=4/8=1/2`

`r=2/4=1/2`

Hence, the common ratio is `1/2` .

Now that the common ratio is known, plug-in its value and the first term to the formula:

`S_(oo)=a_1/(1-r)`

`S_(oo)=8/(1-1/2)=8/(1/2)`

`S_(oo)=16`

**Hence, the sum of the given infinite geometric series is 16. **

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