Find the slope of the line that is perpendicular to the line that passes through the points (1,3) and (2,6)?
The slope of two perpendicular lines m1 and m2 are related as m1* m2 = -1.
The slope of the line through (1,3) and ( 2,6) is :
m = (6 - 3)/(2 - 1)
=> m = 3
A line perpendicular to this line has a slope -1/3.
The slope of the required line is -1/3.
We know that 2 line are perpendicular if and only if the product of the values of their slopes is -1.
We can find the slope of the line that passes through the given points.
m1 = (y2 - y1)/(x2 - x1)
m1 = (6-3)/(2-1)
m1 = 3/1
m1 = 3
The product of the slopes is:
m1*m2 = -1
-3*m2 = -1
We'll divide by -3:
m2 = 1/3
The slope of the perpendicular line to the line that passes through the points (1,3) and (2,6) is m2 = 1/3.