Find the slope ‐ intercept equation of the line with the following properties: Perpendicular to the line x - 4y = 2 containing the point (5,2)
The required line is perpendicular to the line x - 4y = 2. This is the case when the product of the slope of the line and that of x - 4y = 2 is equal to -1.
x - 4y = 2 can be written as y = x/4 - 2/4 in slope intercept form. The slope of the required line is -4.
As it has the point (5, 2) its equation is:
(y - 2)/(x - 5) = -4
=> y - 2 = -4x + 20
=> y = -4x + 22
The equation of the required line in slope-intercept form is y = -4x + 22
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