Find the set values of x so that the geometric series `1+e^x + e^2x +...` converges.Find the exact value of x so that the sum of infinity of this series is 2.

Expert Answers
lemjay eNotes educator| Certified Educator

(a) A geometric series converges if the absolute value of the common ratio is less than 1.

The common ratio of the given series is:


To solve for values of x that make the series to converge, let |r|<1 . 


Using the properties of absolute value, we have

`e^xlt1`            and            `e^xgt-1`

`xltln1`                               `xgtln (-1)`  (Invalid logarithm)


Hence, the geometric series `1+e^x+e^(2x)+..` converges when `xlt0` .

(b) `S_n= 1+ e^x+e^(2x)+...=2`

To solve for x, note that the formula for the sum of infinite geometric series is:

`S_n =sum_(n=0)^oo ar^n = a/(1-r)`

where a is the first term and r is the common ratio.

Substitute `a=1` , `r=e^x` and `S_n=2` .

`2 = 1/(1-e^x)`






Hence, the value of x in the infinite geometric series `1+e^x+e^(2x)+...=2`  is  `x=-ln2` .