Find S_11 for 1 + 2 + 4 + 8 + ...
- print Print
- list Cite
Expert Answers
Tushar Chandra
| Certified Educator
calendarEducator since 2010
write12,551 answers
starTop subjects are Math, Science, and Business
The sum of the first 11 terms of the series 1 + 2 + 4 + 8 + ... has to be determined.
The terms of the sum form a geometric series with 1 being the first term and 2 as the common ratio. For a geometric series the sum of the first n terms is `a*(r^n -1)/(r - 1)`
Substituting the values from the problem `S_11 = 1*(2^11 - 1)/1 = 2048 - 1 = 2047`
The value of `S_11 = 2047`
Related Questions
- find the exact length of the curve, `x=(1/8)y^4+1/(4y^2)` `1<=y<=2` please explain as...
- 1 Educator Answer
- Simplify the product (x+1/x)(x^2+1/x^2)(x^4+1/x^4)(x^8+1/x^8)
- 1 Educator Answer
- the one-to-one functions g and h are defined as follows. g={(-4, -5), (1, 2), (7,1), (8, 5)}...
- 1 Educator Answer
- Find the value of x for the equation 8*2^3x = 4^(x-1).
- 2 Educator Answers
- If a^2 - b^2 = 8 and a*b = 2, find a^4 + b^4.
- 2 Educator Answers