This is regarding arithmetic series.

Common difference(d) = (5-2) = 3

Initial term(a) = 2

The sum of n terms in a arithmetic series is given by;

`S_n = n/2(2a+(n-1)d)`

Therefore;

`S_10 = 10/2(2*2+(10-1)*3)`

`= 5(4+27)`

`= 155`

*So ` S_10 = 155` *

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