`a_n = n^3 - 1`
`a_1 = 1^3 - 1 = 1 - 1 = 0`
`a_2 = 2^3 - 1 = 8 - 1 = 7`
`a_3 = 3^3 - 1 = 27 - 1 = 26`
`a_4 = 4^3 - 1 = 64 - 1 = 63`
`a_5 = 5^3 - 1 = 125-1 = 124`
I saw that these numbers were one less than the cubes. So the answer is
`a_n = n^3 - 1`
We’ll help your grades soar
Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.
- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support
Already a member? Log in here.
Are you a teacher? Sign up now