# Find a rule for finding the nth term of the given sequence 0, 7, 26, 63,...

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### 1 Answer

`a_n = n^3 - 1`

`a_1 = 1^3 - 1 = 1 - 1 = 0`

`a_2 = 2^3 - 1 = 8 - 1 = 7`

`a_3 = 3^3 - 1 = 27 - 1 = 26`

`a_4 = 4^3 - 1 = 64 - 1 = 63`

`a_5 = 5^3 - 1 = 125-1 = 124`

I saw that these numbers were one less than the cubes. So the answer is

`a_n = n^3 - 1`