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You should evaluate the raw score using the next formula:
`z = (x - mu)/sigma`
x represents the raw score, `sigma` represents the standard deviation and `mu` is the mean.
Since the problem offers only the value of z score, you should substitute it in the formula above such that:
`-1.5 = (x - mu)/sigma =gt -1.5 sigma = x - mu`
`x = mu - 1.5 sigma`
Hence, evaluating the raw score if only the z score is given yields `x = mu - 1.5 sigma` .
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