Find mean from the following distribution by step deviation method.Class interval : 15-25 25-35 35-45 45-55 55-65 65-75Frequency : 4 11 19 14 8 2
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In step deviation we have to assume a mean and then do the calculation for findout the actual mean.
Let assumed mean a = 40
Then D = (x-a)/i
Where i is the class interval.
Here i=10
class mid point(x) frequency(f) D=(x-a)/i f*D
15-25 20 4 -2 -8
25-35 30 11 -1 -11
35-45 40 19 0 0
45-55 50 14 1 14
55-65 60 8 2 16
65-75 70 2 3 6
` sum f`= 58 `sumfD` = 17
Mean = a+`sumfD` /`sumf` *i
= 40+(17/58)*10
= 42.93
So the mean of the distribution is 42.93
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