find max and min of f(x,y) = (x - y)^2 xy

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You need to expand the square using the formula `(a-b)^2 = a^2 - 2ab + b^2`  such that:

`f(x,y)= (x^2 - 2xy + y^2)xy => f(x,y) = x^3y - 2x^2y^2 + xy^3`

You need to evaluate the critical points, hence, you need to solve the equations `f_x=0`  and `f_y=0`  such that:

`f_x = 3x^2y -...

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