Find the mass of 3.011 x 10^21 molecules of glucose.  

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Glucose is chemically represented by the formula C6H12O6. That is, each glucose molecule contains 6 atoms of carbon, 12 atoms of hydrogen and 6 atoms of oxygen. 

The molar mass of glucose = (number of carbon atoms x atomic mass of carbon) + (number of hydrogen atoms x atomic mass...

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Glucose is chemically represented by the formula C6H12O6. That is, each glucose molecule contains 6 atoms of carbon, 12 atoms of hydrogen and 6 atoms of oxygen. 

The molar mass of glucose = (number of carbon atoms x atomic mass of carbon) + (number of hydrogen atoms x atomic mass of hydrogen) + (number of oxygen atoms x atomic mass of oxygen)

= (6 x 12) + (12 x 1) + (6 x 16) = 180 g/mole.

Now, 1 mole of a substance contains 6.023 x 10^23 molecules.

Here, we are given 3.011 x 10^21 molecules of glucose. These are equivalent to 

3.011 x 10^21 / (6.023 x 10^23) moles = 0.005 moles of glucose.

Since 1 mole of glucose contains 180 g, 0.005 moles will contain:

0.005 x 180 g = 0.9 g.

Thus, 0.9 g of glucose will contain 3.011 x 10^21 molecules.

Hope this helps.

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