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find the limit as x approaches 1.  f(x)=(ln(x))/(sin(5πx))

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Since this limit is 0/0 so we can use L'Hopital's rule

`lim_(x->1) ln(x)/(sin(5pix)) = lim_(x->1) (1/x)/(5picos(5pix))`

This limit is not 0/0 and can be evaluated `cos(5pi(1)) = -1`

`lim_(x->1) f(x) = (1/1)/(5pi(-1)) = -1/(5pi)`

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