This question requires the fundamental trig limit `lim_{x->0}{sin x}/x=1` .

`lim_{x->0}{sin2x}/{3x}`

`=2/3lim_{x->0}{sin2x}/{2x}`

`=2/3` since we use the fundamental trig limit for the right side

**The trig limit is `2/3.`**

This question requires the fundamental trig limit `lim_{x->0}{sin x}/x=1` .

`lim_{x->0}{sin2x}/{3x}`

`=2/3lim_{x->0}{sin2x}/{2x}`

`=2/3` since we use the fundamental trig limit for the right side

**The trig limit is `2/3.`**