# Find the length and width of a rectangle whose perimeter is equal to 160 cm and its length is equal to triple its width.

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Let the width of the perimeter be "w" and the length be "L"

Given that the perimeter is 160 cm

But the perimeter is given by :

P = 2L + 2W = 160

We will divide by 2.

==> L + w = 80 ............(1)

We are given that the length if triple the width.

Then the length if 3 times the width.

==> L = 3*W

Now we will substitute into (1).

==> L + w = 80

==> 3w + w = 80

==> 4w = 80

==> w = 80/4 = 20

==> L = 3*20 = 60

**Then the length of the rectangle = 60 cm, and the width = 20 cm**

The length of the rectangle is equal to triple its width and the perimeter is 160 cm.

Let the length be l and the width be w.

Now l = 3w

Also, perimeter = 2(l+w) = 2*( 3w + w) = 160

=> 2*4w = 160

=> 8w = 160

=> w = 20

**Therefore the width of the rectangle is 20 cm and the length is 60 cm.**

Q:Find the length and width of a rectangle whose perimeter is equal to 160 cm and its length is equal to triple its width.

A:

Perimeter P =2(l+w) , where l is lenth and w is width.

Given l = 3w.

So P = 2(l+w) = 2(3w+w) = 8w.

P= 160=> 8w = 160 cm.

w = 160/8 = 20cm.

Therefore l = 3w = 3*20 cm = 60 cm.

**Therefore length and width of the rectangle are 60 cm and 20 cm respectively.**