Find the length and width of a rectangle whose perimeter is equal to 160 cm and its length is equal to triple its width.
Let the width of the perimeter be "w" and the length be "L"
Given that the perimeter is 160 cm
But the perimeter is given by :
P = 2L + 2W = 160
We will divide by 2.
==> L + w = 80 ............(1)
We are given that the length if triple the width.
Then the length if 3 times the width.
==> L = 3*W
Now we will substitute into (1).
==> L + w = 80
==> 3w + w = 80
==> 4w = 80
==> w = 80/4 = 20
==> L = 3*20 = 60
Then the length of the rectangle = 60 cm, and the width = 20 cm
The length of the rectangle is equal to triple its width and the perimeter is 160 cm.
Let the length be l and the width be w.
Now l = 3w
Also, perimeter = 2(l+w) = 2*( 3w + w) = 160
=> 2*4w = 160
=> 8w = 160
=> w = 20
Therefore the width of the rectangle is 20 cm and the length is 60 cm.
Q:Find the length and width of a rectangle whose perimeter is equal to 160 cm and its length is equal to triple its width.
Perimeter P =2(l+w) , where l is lenth and w is width.
Given l = 3w.
So P = 2(l+w) = 2(3w+w) = 8w.
P= 160=> 8w = 160 cm.
w = 160/8 = 20cm.
Therefore l = 3w = 3*20 cm = 60 cm.
Therefore length and width of the rectangle are 60 cm and 20 cm respectively.