We have the rectangle ABCD A(1,2) B(1,5) C(3,5) D(3,2)
Let us calculate lenghth and width:\
AB = sqrt(1-1)^2 - (5-2)^2] = sqrt3^2 = 3\
BC = sqrt[(3-1)^2 + (5-5)^2] = sqrt2^2 = 2
CD = sqrt[(3-3)^2 + (5-2)^2] = sqrt3^2 = 3
AD = sqrt[(3-1)^2 + (2-2)^2] = sqrt2^2 =...
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We have the rectangle ABCD A(1,2) B(1,5) C(3,5) D(3,2)
Let us calculate lenghth and width:\
AB = sqrt(1-1)^2 - (5-2)^2] = sqrt3^2 = 3\
BC = sqrt[(3-1)^2 + (5-5)^2] = sqrt2^2 = 2
CD = sqrt[(3-3)^2 + (5-2)^2] = sqrt3^2 = 3
AD = sqrt[(3-1)^2 + (2-2)^2] = sqrt2^2 = 2
Then we have the length (L) = 3 and width (W) = 2
Then the diaginal is:
d = sqrt(L^2 + W^2)
= sqrt(9 + 4) = sqrt13
==> The diagonal length is d= sqrt13