Find the length of the arc formed by `y= 1/(8(-2x^2+4ln(x)))`  from x = 3 to x = 8.

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You need to use the following formula to evaluate the given arclength such that:

`l = int_a^b sqrt(1 + (f'(x))^2)dx`

Reasoning by analogy yields:

`int_3^8 sqrt(1 + ((1/8(-2x^2+4ln(x)))')^2)dx`

You need to evaluate the derivative of the function `f(x) = 1/8(-2x^2+4ln(x))` , using...

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