We have the function f(x) = -2ln(2x-3) + 2

Let y = f(x) = -2*ln (2x - 3) + 2

=> y - 2 = -2*ln (2x - 3)

=> -(y-2)/2 = ln (2x - 3)

=> e^ ( (2-y)/2)) = 2x - 3

=> 2x = 3 + e^( (2-y)/2))

=> x = [3 + e^( (2-y)/2))]/2

=> x = 3/2 + e^(1 - y/2)/2

(The entire section contains 2 answers and 187 words.)

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