# Find the inverse of f(x) = x^2-4x+3. Is the inverse a function?

Asked on by cammy17

kyouraku | Student, Undergraduate | (Level 1) eNoter

Posted on

lol heres the REAL anwser.

y=x^2-4x+3 ( you have to complete the square here)

y=(x^2-4x+(2)^2-(2)^2)+3
y=(x^2-4x+4-4)+3 Rearrange the brackets to take -4 out

y=(x^2-4x+4)-4+3
y=(x^2-4x+4)-1 Simplify the things in the bracket
y=(x-2)^2-1

Now switch places with x and y

x=(y-2)^2-1 solve for y

x+1=(y-2)^2  square root both sides (square root=Sqrt)

plus/minus Sqrt(x+1)=y-2
y=2 plus/minus Sqrt(x+1) and nope it's not a function

neela | High School Teacher | (Level 3) Valedictorian

Posted on

f(x) = x^2-4x-3. Or

y = x^2-4x-3.

For a given value y ,

y=x^2-4x-3. Or

x^2-4x-3-k = 0. Solving for x ,

x = {4 +or- sqrt(4^2+4(3+y)}/2.

x = 2+2sqrt(4+y) Or where when x>2, y = 2+2sqrt(4+x) is the inverse.

x =2-2sqrt(4+y). Or when x <2, y = 2-sqrt(4+x) is the inverse.

One value of y shares double value of x. So the inverse is not a function.

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