# Find the intercepts of the line L given by (-1/2)y - 12 = x

*print*Print*list*Cite

### 2 Answers

We need the intercepts of the line (-1/2)y - 12 = x

(-1/2)y - 12 = x

=> (-1/2)y - x = 12

=> (-1/2)y/12 - x/12 = 1

=> y/(-24) + x/(-12) = 1

This is of the form x/a + y/b = 1, where a and b are the x and y intercepts respectively.

**So the intercepts of the line are (-12, 0) and (0, -24)**

Given the line (-1/2)y -12 = x

We need to find the intercepts ( x-intercept and y-intercept).

Let us determine the y-intercept.

The y-intercept is the point where the line intersects with the y-axis.

Then the values of x will be zero.

==> (-1/2)y -12 = 0

==> -1/2 y= 12

==> -y = 24

==> y= -24

Then the y-intercept is the point (0, -24).

Now we will determine the x-intercept.

The x-intercept is the point where the line meets the x-axis.

Then the value of y is 0.

==> (-1/2)*0 - 12 = x

==> x = -12

==> x-intercept is the point ( -12, 0)

**Then the intercepts are : (x-intercept is ( -12,0) and y-intercept is ( 0, -24)**