Find the integral(-x^8+4)^6 x^7

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embizze eNotes educator| Certified Educator

Evaluate `int(-x^8+4)^6x^7dx` :

You can use the Fundamental Theorem of calculus directly:

Note that the derivative of `-x^8+4` is`-8x^7dx` , so we multiply the integrand by -8 and ` ``-1/8` to get:

`int -1/8((-x^8+4)^6-8x^7)dx` or `-1/8 int-8x^7(-x^8+4)^6dx`

This is of the form `int F(x)F'(x)dx` so by the FTC we get:


`int (-x^8+4)^6x^7dx=-1/8int-8x^7(-x^8+4)^6dx`

`=-1/8[1/7(-x^8+4)^7+C_1]=-1/56(-x^8+4)^7+C` which is the solution.


** You can check by differentiating:



*** You could use a `u-` substitution:

Let `u=-x^8+4,(du)/(dx)=-8x^7`

Then `int(-x^8+4)^6x^7dx=-1/8intu^6du=-1/8(1/7u^7+C_1)`



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