1 Answer | Add Yours
Number of ways to select 1st digit = 7
Number of ways to select 2nd digit = 6
Number of ways to select 3rd digit = 5
Number of ways to select 4th digit = 4
So with out repetition number of 4-digit numbers that can be formed are `7xx6xx5xx4 = 840` .
We have 3 odd number and 4 even number in the set.
Ways to select two odds `= ^3C_2 = 3`
Ways to select two even `= ^4C_2 = 6`
Number of 4-digit numbers with two even and two odd `3xx6 = 18`
But we can rearrange these four digits within the number.
So total number of ways `= 18xx4! = 432`
So we can form 432 four digit numbers for the given condition.
We’ve answered 319,200 questions. We can answer yours, too.Ask a question