Find the horizontal and vertical components of the velocity of:
a ball which is released out of the window of a plane which is traveling horizontally with a speed of 100 km/hr and of a cat which jumps out of the back of a truck at an angle of 30 degrees above horizontal with a velocity of 5m/s relative to the truck and the truck is moving at 40km/hr
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1. The ball released from the window of a plane travelling horizontal with a speed of 100 km/hr:
As the ball is released and NOT thrown downwards, therefore it will have no effect on the horizontal or vertical components of the ball speed.
Horizontal component of velocity of ball = horizontal velocity of plane Vertical component of velois 100 km/hr
Vertical component of velocity of the ball = 0 km/hr
2. Speed of truck =40 km/hr. The cat jumps from the back with a speed of 5 m/s relative to the truck at an angle of 30 degrees above horizontal.
As the cat jumps from te back of the truck so its direction is opposite to the direction of truck - assumed. Further it jumps up so its direction is upwards.
The speed of turck = 40 km/hr = 40*1000/3600 = 11.11 m/s
The horizontal component of cats velocity = 11-5*cos(30)= 11.11-4.33 = 6.78 m/s in the direction of truck.
This means the cat will roll back on hitting the ground as it is moving in the direction of the truck with face to the truck's back.
The vertical component of the cats velocity = 5.sin(30) = 2.5 m/s in the upwards direction.
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