Find the gradient of the curve y = ln(5x + 1) at the point where x = 4

Expert Answers

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`y = ln(5x + 1)`

The gradient of the above curve at any point is given by the first derivative.


`dy/dx=[1/(5x+1)] xx 5 = 5/(5x+1)`

Gradient at x=4 is given by;

`(dy/dx)_(x=4) = [5/(5 xx 4 +1)] = 5/21`

So the gradient of curve at x=4 is 5/21

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