# Find the general term that discribes the sequence: -12, -8, -4, 0

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The terms of sequence are -12, -8, -4 and 0

-12 = 4*-3

-8 = 4*-2

-4 = 4*-1

0 = 4*0

The general term is `t_n = 4*(n - 4)`

**The general term of the terms of the series -12, -8, -4, 0 is **`t_n = 4*(n - 4)`

The term sequence -12, -8, -4, 0 have a common difference of -4 as can be seen below:

Common difference = (-8)-(-12) = (-4)-(-8) = (0)-(-4) = 4

This is an arithmatic progression with the first term as -12 and common difference as 4

The general term Tn = First Term + Common Difference *(n-1)

Tn = -12+4*(n-1) = 4n-16 = 4.(n-4), where n is the Term Number

**The general term is Tn = 4.(n-4), where n is the term number**

1st term = 4.(1-4) = -12

2nd term = 4.(2-4) = -8

3rd term = 4.(3-4) = -4

4th term = 4.(4-4) = 0 and so on